Question 1

How do you calculate the winning probability in Eurojackpot?

Accepted Answer

The winning probability in Eurojackpot is calculated using combinatorics. From 50 main numbers, 5 are drawn — resulting in C(50,5) = 2,118,760 combinations. Additionally, 2 Euro numbers from 12 are drawn: C(12,2) = 66 combinations. The total is 2,118,760 × 66 = 139,838,160 possible combinations. Our probability calculator shows the exact calculation for all 12 prize classes with the underlying mathematical formulas.

Question 2

Can you mathematically calculate or predict Eurojackpot numbers?

Accepted Answer

No — Eurojackpot numbers cannot be predicted. Each draw is a completely independent random event. The balls have no memory: Whether a number appeared 100 times in a row or hasn’t been drawn for years doesn’t change the probability of the next draw. Statistical analyses of past draws can reveal patterns, but these have no predictive value whatsoever.

Question 3

How many combinations are there in Eurojackpot?

Accepted Answer

There are a total of 139,838,160 different total combinations in Eurojackpot. For the 5 main numbers from 50, there are C(50,5) = 2,118,760 combinations; for the 2 Euro numbers from 12, there are C(12,2) = 66 combinations. Multiplied together, this gives the total. Per ticket, you therefore have a chance of approximately 1 in 140 million for the jackpot.

Question 4

Are there numbers with a higher winning probability?

Accepted Answer

Mathematically speaking, each of the 139,838,160 combinations has exactly the same probability of being drawn. There are no ‘better’ or ‘worse’ numbers. Rarely played combinations (e.g., numbers above 31, no geometric patterns) are not drawn more often either. They only affect how many other players a prize would probably have to be shared with in the event of a hit — not the chance of the hit itself.

Question 5

How likely is it to win in Eurojackpot?

Accepted Answer

The probability depends on the prize class: For 5+2 (jackpot), it is 1 in 139,838,160. For 5+1, it is 1 in 6,991,908. The ‘easiest’ prize class (2+1) has odds of 1 in 49. Overall, statistically about every 32nd ticket wins a prize.

Class	Condition	Probability	Formula
1	5 Richtige + 2 Eurozahlen	1:139.838.160	C(5,5)×C(45,0)/C(50,5) × C(2,2)×C(10,0)/C(12,2)
2	5 Richtige + 1 Eurozahl	1:6.991.908	C(5,5)×C(45,0)/C(50,5) × C(2,1)×C(10,1)/C(12,2)
3	5 Richtige	1:3.107.515	C(5,5)×C(45,0)/C(50,5) × C(2,0)×C(10,2)/C(12,2)
4	4 Richtige + 2 Eurozahlen	1:621.503	C(5,4)×C(45,1)/C(50,5) × C(2,2)×C(10,0)/C(12,2)
5	4 Richtige + 1 Eurozahl	1:31.075	C(5,4)×C(45,1)/C(50,5) × C(2,1)×C(10,1)/C(12,2)
6	3 Richtige + 2 Eurozahlen	1:14.125	C(5,3)×C(45,2)/C(50,5) × C(2,2)×C(10,0)/C(12,2)
7	4 Richtige	1:13.811	C(5,4)×C(45,1)/C(50,5) × C(2,0)×C(10,2)/C(12,2)
8	2 Richtige + 2 Eurozahlen	1:985	C(5,2)×C(45,3)/C(50,5) × C(2,2)×C(10,0)/C(12,2)
9	3 Richtige + 1 Eurozahl	1:706	C(5,3)×C(45,2)/C(50,5) × C(2,1)×C(10,1)/C(12,2)
10	3 Richtige	1:314	C(5,3)×C(45,2)/C(50,5) × C(2,0)×C(10,2)/C(12,2)
11	1 Richtige + 2 Eurozahlen	1:188	C(5,1)×C(45,4)/C(50,5) × C(2,2)×C(10,0)/C(12,2)
12	2 Richtige + 1 Eurozahl	1:49	C(5,2)×C(45,3)/C(50,5) × C(2,1)×C(10,1)/C(12,2)

Calculating Eurojackpot combinations — the basics

All 12 prize classes

Eurojackpot probabilities — visual representation

Eurojackpot winning probability vs. everyday life

Frequently asked questions about Eurojackpot probability

Probability Calculator

Calculating Eurojackpot combinations — the basics

All 12 prize classes

Eurojackpot probabilities — visual representation

Eurojackpot winning probability vs. everyday life

Frequently asked questions about Eurojackpot probability